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Wednesday, 1 May 2013
Reverse Of a No.
#!/bin/sh
echo -n "Enter any no to find Reverse : "
read n
p=$n
rev=0
while [ $n -gt 0 ]
do
z=$(($n%10))
n=$(($n/10))
rev=$(($(($rev*10)) + z))
done
echo " .............reverse of the no. is : ........ : $rev"
exit 0
Output :
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